A taxi charges in a city comprise of a fixed charge together with charge for distance covered. For a journey of 10km the charge paid was 75Rs and for 15km the charge was 110Rs. Find the charge for 25km.

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Solution

Let fixed charges of taxi be Rs.x and charges for covering distance be Rs.y per km.
Then according to question, we have
x+10y=75 (i)
x+15y=110 (ii)
Solve
we get x=5 and y=7
Person will have to pay for travelling a distance of 25 km.
x+25y=5+25*7=Rs.180

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A taxi charges in a city comprise of a fixed charge together with charge for distance covered. For a journey of 10km the charge paid was 75Rs and for 15km the charge was 110Rs. Find the charge for 25km.

Let fixed charges of taxi be Rs.x and charges for covering distance be Rs.y per km. Then according to question, we have x+10y=75 (i) x+15y=110 (ii) Solve we get x=5 and y=7 Person will have to pay for travelling a distance of 25 km. x+25y=5+25*7=Rs.180

Let fixed charges of taxi be Rs.x and charges for covering distance be Rs.y per km.
Then according to question, we have
x+10y=75 (i)
x+15y=110 (ii)
Solve
we get x=5 and y=7
Person will have to pay for travelling a distance of 25 km.
x+25y=5+25*7=Rs.180