A telephone company charges ₹0.05 per minute for local calls and ₹0.12 per minute for long distance calls. Which expression gives the total cost in rupees for " $x$ " minutes of local calls and " $y$ " minutes of long distance calls?

0.05 x + 0.12 y

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0.05 x - 0.12 y

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0.17 (x + y)

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0.17 x y

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Solution

The correct option is A $0.05 x + 0.12 y$
Given, the charges for local and long distance calls are ₹0.05 per minute and ₹0.12 per minute respectively.

Total minutes of local call is = x
Total minutes of long distance call is = y

$∴$ The required algebraic expression is₹ $(0.05 x + 0.12 y)$ .

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Similar questions

The number ot telephone calls received at an exchange per interval for 250 successive one-minute intervals are given in the following frequency table:
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Q. The number of telephone calls received at an exchange per interval for 250 successive one-minute intervals are given in the following frequency table:

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A telephone company charges ₹0.05 per minute for local calls and ₹0.12 per minute for long distance calls. Which expression gives the total cost in rupees for "x" minutes of local calls and "y" minutes of long distance calls?

The correct option is A 0.05x+0.12y Given, the charges for local and long distance calls are ₹0.05 per minute and ₹0.12 per minute respectively. Total minutes of local call is = x Total minutes of long distance call is = y ∴ The required algebraic expression is₹ (0.05x+0.12y).

A telephone company charges ₹0.05 per minute for local calls and ₹0.12 per minute for long distance calls. Which expression gives the total cost in rupees for " $x$ " minutes of local calls and " $y$ " minutes of long distance calls?