Question

A telephone link operating at a central frequency of 10 GHz is established. If 1% of this is available then how many telephone channel can be simultaneously given when each telephone covering a band width of 5 kHz

• A. 2 $\times {10}^4$
• B. 2 $\times {10}^6$
• C. 5 $\times {10}^4$
• D. 5 $\times {10}^6$

Answer 1

The correct option is A 2 $\times {10}^4$

1 % of 10 GHz = 10 $\times {10}^9\times \frac{1}{100}={10}^{8}Hz$
Number of channels = $\frac{{10}^8}{5\times {10}^3}=2\times {10}^4$