A tent is in the form of a cylinder of diameter 15 m and height 2.4 m, surmounted by a cone of equal base and height 4 m. Find the capacity of the tent and the cost of the canvas at Rs. 50 per square meter.

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Solution

Given diameter of cylinder=15ms
∴ radius=15ms/2=7.5ms
height=2.4ms
surface area of cylinder =2πrh
=222/77.52.4 mm
=113.14m m
since it is given equal base radius is also equal
∴radius of cone =7.5ms
given height =4m
∴l=√hh+rr
l=√44+7.57.5
l=13.275
c.s.a. of cone =πrl
=22/7 7.513.2 =312.91mm
total surface area = c.s.a of cylinder +c.s.a of cone
=113.14+312.91 =426.05mm
cost of canvas per m square =50RS
∴cost of canvas required=426.0550 =21302.5 RS

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