Question

A tent is in the form of a right circular cylinder surmounted by a cone. The diameter of cylinder is 24 m. The height of the cylindrical portion is 11 m while the vertex of the cone is 16 m above the ground.Find the area of canvas required for the tent.

Answer 1

CSA of cylinder=2*pi*r*h
=2×22/7×24/2×11
=829.71 m^2
Then,
slant height=root r^2+h^2
=root 12^2+(16-11)^2
=root 144 + 25
Hence, slant height=13 m
Now,
CSA of cone=pi*r*l
=22/7×12×13
=490.28 m^2
Then,
Total area of canvas required for tent
=829.71+490.28
=1319.99 m^2
Hope it helps u.