Question

A tent is in the form of a right circular cylinder, surmounted by a cone. The diameter of the cylinder is $24$ m. The height of the cylindrical portion is $11$ m, while the vertex of the cone is $16$ m above the ground.

The curved surface area of the cylindrical portion is

• A. $\left(246\pi \right)m^2$
• B. $\left(264\pi \right)m^2$
• C. $\left(426\pi \right)m^2$
• D. $\left(462\pi \right)m^2$

Answer 1

Answer: (B)

$\left(264\pi \right)m^2$

Given, diameter $=24$ m

Therefore, radius $=\frac{d}{2}=\frac{24}{2}=12$ m

and height given is $11$ m

Therefore, curved surface area of the cylinder $=2\left(\pi \right)rh$

$=2\times \left(\pi \right)\times 12\times 11$

$=264\left(\pi \right)$