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Question

A tent is in the form of a right circular cylinder surmounted by a cone.The diameter of cylinder is 24 m.The height of the cylindrical portion is 11 m while the vertex of the cone is 16 m above the ground.Find the area of the canvas required for the tent.

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Solution

Diameter of the cylindrical portion = 24 m

Radius (r)=242=12 m

Height of cylindrical portion=11 m

and total height= 16 m

Height of conical portion=1611=5 m

Slant height of the conical portion (l)=r2+h2=(12)2+(5)2=144+25=169=13 mNow area of canvas used in it =2πrh+πrl=πr(2h+l)=227×12(2×11+13) m2=2647(22+13)=2647×35 m2=1320 m2


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