Question

A test plate 30 cm square, settles by 12 mm under a load of 4.5 kN in a sandy soil. By how much will a footing $2m\times 2m$ subjected to a load of 200 kN settle?

• A. 36.3 mm
• B. 20.87 mm
• C. 75.75 mm
• D. 18.15 mm

Answer 1

The correct option is A 36.3 mm

Load intensity for 4.5 kN load on 30 cm square plate will be

$q=\frac{4.5}{(0.3{)}^2}=50kN/m^2$

Load intensity for 200kN load on $2m\times 2m$ footing will be

$q^{\prime }=\frac{200}{4}=50kN/m^2$

Since load intensity is same so,

$S_f=S_p\times {\left(\frac{B_f(B_P+0.3)}{B_P(B_f+0.3)}\right)}^2$

$=12\times {\left(\frac{2\times 0.6}{0.3\times 2.3}\right)}^2$

= 36.3 mm