A PNP in common emitter configuration used as an amplifier, its current gain is 50. If input resistance is 1kΩ and input voltage is 5V , then output current will be-
A
250mA
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B
30mA
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C
50mA
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D
100mA
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Solution
The correct option is A250mA Given,
RB=1kΩ;VB=5V;β=50
From Ohm's law, V=IR
IB=VBRB=5×10−3A(or)
IB=5mA
IC=βIB=50×5×10−3=250mA
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Hence, (A) is the correct answer.