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Question

A PNP in common emitter configuration used as an amplifier, its current gain is 50. If input resistance is 1 kΩ and input voltage is 5 V , then output current will be-

A
250 mA
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B
30 mA
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C
50 mA
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D
100 mA
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Solution

The correct option is A 250 mA
Given,

RB=1 kΩ ; VB=5 V ; β=50

From Ohm's law, V=IR

IB=VBRB=5×103 A (or)

IB=5 mA

IC=β IB=50×5×103=250 mA

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (A) is the correct answer.

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