Question

A thermo dynamical system undergo cyclic process ABCDA as shown in figure. Work done by the system is:

• A. Zero
• B. $2P_o{V}_o$
  
• C. $P_{o}V$
• D. $\frac{3}{2}{P}_o{V}_o$

Answer 1

The correct option is A Zero


$W_{AEDA}$ = + Area of $\Delta AED$
$=\frac{1}{2}\times P_o{V}_o$ W = +ve (clockwise)
$W_{BCEB}$ = - Area of $\Delta BCE$
$=-\frac{1}{2}\times P_o{V}_o$ W=– ve (Anticlockwise)
$W_{net}=W_{AEDA}+W_{BCEB}$
$W_{net}=0$