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Question

A thermodynamic cycle is comprised of four processes 12 , 23 , 34 and 41 . Heat & work interactions of these processes are given as

Process Heat transfer (J) Work done (J)
1-2 0 150 (by the gas)
2-3 100 (from the gas) 0
3-4 0 50 (on the gas)
4-1 200 (to the gas) 0

The thermal efficiency of the cycle is -

A
20 %
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B
30 %
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C
40 %
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D
50 %
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Solution

The correct option is D 50 %
From the given data, we can find the efficiency of the cyclic process by using
η=Work outputHeat input=1(Heat rejectedHeat added)
From the data given in the question,
η=1100200= 50 %
Thus, option (d) is the correct answer.

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