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Question

A thermodynamic process, 200 J of heat is given to a gas and 100 J of work is also done on it. The change in internal energy of the gas is

A
100 J
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B
300 J
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C
419 J
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D
24 J
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Solution

The correct option is A 100 J
ΔU=QW [From !st law of thermodynamics]
Q=200J
W=100J
ΔU=(200100)J=100J



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