In a thermodynamic process pressure of a fixed mass of a gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas if the initial internal energy of the gas was 30 J. The final internal energy wilI be:

26 J

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15 J

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18 J

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9 J

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Solution

The correct option is C 18 J
dQ = -20J, dW = -8 J, $U_{1} = 30 J$
By 1st law of thermodynamics,
dQ = dU + dW
$\Rightarrow$ dU = dQ-dW
= -20 + 8 = -12J
Final internal energy, $U_{2} = U_{1} + d U$
= 30-12 = 18 J

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In a thermodynamic process pressure of a fixed mass of a gas is changed in such a manner that the gas releases 20 J of heat and 8 J of work is done on the gas if the initial internal energy of the gas was 30 J. The final internal energy wilI be:

The correct option is C 18 JdQ = -20J, dW = -8 J, U1=30JBy 1st law of thermodynamics,dQ = dU + dW⇒ dU = dQ-dW= -20 + 8 = -12JFinal internal energy, U2=U1+dU= 30-12 = 18 J

The correct option is C 18 J
dQ = -20J, dW = -8 J, $U_{1} = 30 J$
By 1st law of thermodynamics,
dQ = dU + dW
$\Rightarrow$ dU = dQ-dW
= -20 + 8 = -12J
Final internal energy, $U_{2} = U_{1} + d U$
= 30-12 = 18 J