Question

A thermodynamic system goes from states (i) $P_1,V$ to $2P_1,V$ and
$\left(ii\right)P,V_{1}toP,2V_1$
The work done in the two cases respectively is:

• A. Zero, Zero
• B. Zero, $-P{V}_1$
• C. $-P{V}_1,$ Zero
• D. $-P{V}_1,-P_1{V}_1$

Answer 1

The correct option is B Zero, $-P{V}_1$

Work done is given as:
$W=-P(V_f-V_i)$
$P$ = Pressure of the system
$V_f$ = Final volume of the system
$V_i$ = Initial volume of the system

Case (i), as volume is not changing,
$△V=0,so,W=0$

Case (ii), P = constant
$W=-P(V_f-V_i)=-P(2V_1-V_1)=-P{V}_1$