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Standard XII

Physics

Heat Capacity

A thermodynam...

Question

A thermodynamic system is taken through the cycle abcda, find the total heat rejected by the gas during the process-

10 J

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20 J

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30 J

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40 J

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Solution

The correct option is B $20 J$
$P = 100$ k Pa
$V = 100 c m^{3}$
We know that for given cyclic process $Δ U = 0$
$∴ Q = W$
Also $W = -$ (area enclosed by P-V curve)
$= - P \times 2 V$
$∴$ Heat rejected $= - (- W)$
$= W$
$= 2 P V$ .
Heat $= 420$ J.

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A thermodynamic system is taken through the cycle abcda, find the total heat rejected by the gas during the process-

The correct option is B 20JP=100k PaV=100cm3We know that for given cyclic process ΔU=0∴Q=WAlso W=−(area enclosed by P-V curve)=−P×2V∴ Heat rejected =−(−W)=W=2PV.Heat=420J.

The correct option is B $20 J$
$P = 100$ k Pa
$V = 100 c m^{3}$
We know that for given cyclic process $Δ U = 0$
$∴ Q = W$
Also $W = -$ (area enclosed by P-V curve)
$= - P \times 2 V$
$∴$ Heat rejected $= - (- W)$
$= W$
$= 2 P V$ .
Heat $= 420$ J.