A thermodynamic system is taken through the cycle PQRSP process. The net work done by the system is
A
20 J
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B
-20 J
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C
400 J
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D
-374 J
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Solution
The correct option is B-20 J Work done by the system = Area of shaded portion on P-V diagram =(300−100)10−6×(200−10)×103=20J and direction of process is anticlockwise so work done will be negative i.e. ΔW=−20J