Question

A thermodynamic system undergoes cyclic process $ABCDA$ as shown in figure. The work done by the system is

• A. $P_0{V}_0$
• B. $2P_0{V}_0$
• C. $\frac{P_0{V}_0}{2}$
• D. zero

Answer 1

The correct option is D zero

From the figure,

Work done in process ODA= Area of triangleAOD=$\frac{1}{2}\times P_0\times V_0$

While work done in the process OBC=-Area of triangleBCO=$-\frac{1}{2}\times P_0\times V_0$

so,

$W_{net}=0$