Question

A thermodynamics system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is

• A. $P_0{V}_0$
• B. $2P_0{V}_0$
• C. $\frac{P_0{V}_0}{2}$
• D. 0.0

Answer 1

The correct option is D 0.0

Work done in process $ODA=\frac{1}{2}\times P_0\times V_0$
While work done in the process $OBC=-\frac{1}{2}{P}_0{V}_0$
So net work done is 0.