Question

A thief is spotted by a policeman from a distance of $100$ metres. When the policeman starts the chase the thief also starts running. If the speed of the thief is $8$ km/hr and that of the policeman $10$ km/hr, how far the thief will have to run before he is overtaken ?

• A. $300$ m
• B. $350$ m
• C. $400$ m
• D. $450$ m

Answer 1

The correct option is C $400$ m

$1000m=1km$
the distance is $\frac{100}{1000}=.1km$
let time $=x$
$10x=0.1+8x$
$2x=0.1$
$x=0.05$
it will take the policeman $.05hours$ to catch the thief
the thief would have run $.05\times 8=.4km=400meters$