Question

# A thin spherical conduction shell of radius R has a charge q. another charge Q is placed atthe centre of the shell. The electrostatic potential at a point P at a distance R$$/2$$ from thecentre of the shell is

A
2Q4πε0R
B
2Q4πϵ0R2q4πε0R
C
2Q4πϵ0R+q4πε0R
D
(q+Q)4πε02R

Solution

## The correct option is B $$\displaystyle \dfrac{2\mathrm{Q}}{4\pi\epsilon_{0}\mathrm{R}}+\dfrac{\mathrm{q}}{4\pi\varepsilon_{0}\mathrm{R}}$$Here the point is inside the shell. so, the potential at P $$=$$ potential due to charge Q$$+$$ potential at surface of shellor $$V_P=\dfrac{Q}{4\pi\epsilon_0(R/2)}+\dfrac{q}{4\pi\epsilon_0 R}$$PhysicsNCERTStandard XII

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