A thin uniform rod is of mass M and length L. Find the radius of gyration for rotation about an axis passing through a point at a distance of L4 from the centre and perpendicular to the rod is √n48L.Then n is
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Solution
As we know, MOI of the rod about axis passing through its centre and perpendicular to the rod =ML212 By parallel axis theorem, MOI about new axis:- =ML212+M(L4)2=MK2 ⇒L212+L216=K2 or K=√748L So, n=7