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Question

Find the M.I. of a thin uniform rod about an axis perpendicular to tis length and passing through a point which is at a distance "l3" from one end. Then the radius of gyration about that axis.
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A
l3
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B
l2
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C
l4
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D
l6
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Solution

The correct option is A l3
Let R be radius of gyration
Moment of inertia through centre of rod is Ml212
Moment of inertia through a point at a distance is l3 from one end is equal to a distance of l6 from the centre of rod is
Ml212+M(l6)2=Ml29
Ml29=MR2
R=l3




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