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Question

A three-digit number XYZ is formed of three different non-zero digits X,Y and Z. A new number is formed by rearranging the same three digits. What is the greatest possible difference between the two numbers? (For example, 345 could be rearranged into 435, for a difference of 435345=90.)

A
792
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B
293
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C
564
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D
984
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E
456
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Solution

The correct option is D 792
To get the greatest difference, we want to subtract a small number from a large one, so we will need the digit 9 and 1,to make numbers in 100s and the number 900s.
Let m be the digit from 2 to 8.
The larger three digit number will look like 9m1, while the smaller three digit number will look like 1m9.
Assume a three digits number lets say 189.
Then the largest possible three digit number after rearranging above number is 981.
981189=792
Again assume
a three digits number lets say 149.
Then the largest possible three digit number after rearranging above number is 941.
941149=792

As you see no matter what is the value you are plugging for m their difference is constant i.e:792, which is the highest possible difference.
Hence, option A is correct.

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