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Question

# A three-span continuous beam has an internal hinge at B. Section B is at the mid-span of AC. Section E is at the mid-span of CG. The 20 kN load is applied at section B whereas 10 kN loads are applied at sections D and F as shown in the figure. Span GH is subjected to uniformly distributed load of magnitude 5 kN/m. For the loading shown, shear force immediate to the right of section E is 9.84 kN upwards and the hogging moment at section E is 10.31 kN-m. AB = BC = 2 m ; CD = DE = EF = FG = 1 m; GH = 4 m The magnitude of the shear force immediate to the left and immediate to the right of section B are, respectively

A
0 & 20 kN
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B
10 kN & 10 kN
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C
20 kN & 0
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D
9.84 kN & 10.16 kN
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Solution

## The correct option is A 0 & 20 kN AB = BC = 2m CD = DE = EF = FG = 1m GH = 4m B is internal hinge So ∑M=0 RA×AB=0 ⇒ RA=0 Shear force immediate to the left of B RA=0 Shear force immediate to the right of B RA−20=20kN

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