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Question

A three-span continuous beam has an internal hinge at B. Section B is at the mid-span of AC. Section E is at the mid-span of CG. The 20 kN load is applied at section B whereas 10 kN loads are applied at sections D and F as shown in the figure. Span GH is subjected to uniformly distributed load of magnitude 5 kN/m. For the loading shown, shear force immediate to the right of section E is 9.84 kN upwards and the hogging moment at section E is 10.31 kN-m.

AB = BC = 2 m ; CD = DE = EF = FG = 1 m; GH = 4 m

The vertical reaction at support H is

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Solution

The correct option is **B** 9.84 kN upward

ME=10.31kNm

Shear force right of section E0

V+E=9.84KN upward

Hogging moment at E,

ME=10.31kNm

At support G

Hogging moment from left side = Hogging moment from right side

10.31+10×1−9.84×2

=5.(4)22 −RH×4

⇒ RH=9.84kN (upward)

ME=10.31kNm

Shear force right of section E0

V+E=9.84KN upward

Hogging moment at E,

ME=10.31kNm

At support G

Hogging moment from left side = Hogging moment from right side

10.31+10×1−9.84×2

=5.(4)22 −RH×4

⇒ RH=9.84kN (upward)

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