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Question

# A three-span continuous beam has an internal hinge at B. Section B is at the mid-span of AC. Section E is at the mid-span of CG. The 20 kN load is applied at section B whereas 10 kN loads are applied at sections D and F as shown in the figure. Span GH is subjected to uniformly distributed load of magnitude 5 kN/m. For the loading shown, shear force immediate to the right of section E is 9.84 kN upwards and the hogging moment at section E is 10.31 kN-m. AB = BC = 2 m ; CD = DE = EF = FG = 1 m; GH = 4 m The vertical reaction at support H is

A
15 kN upward
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B
9.84 kN upward
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C
15 kN downward
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D
9.84 kN downward
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Solution

## The correct option is B 9.84 kN upward ME=10.31kNm Shear force right of section E0 V+E=9.84KN upward Hogging moment at E, ME=10.31kNm At support G Hogging moment from left side = Hogging moment from right side 10.31+10×1−9.84×2 =5.(4)22 −RH×4 ⇒ RH=9.84kN (upward)

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