Question

A ticket is picked up randomly from tickets numbered 1 to 20. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

• A. 9/20
• B. 11/20
• C. 13/20
• D. 1/2
• E. none

Answer 1

The correct option is A

9/20

Here, S = {1, 2, 3, 4, ....,19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

So P(E) = $\frac{9}{20}$.