Question

A tin holds $16.5\mathrm{litres}$ of oil. How many such tins will be required to hold $313.5\mathrm{litres}$ of oil?

Answer 1

Capacity of a tin$=16.5\mathrm{litres}$

Total amount of oil$=313.5\mathrm{litres}$

$\begin{array}{rcl}\mathrm{Number}\mathrm{of}\mathrm{tins}\mathrm{required}& =& \frac{\mathrm{Total}\mathrm{amount}\mathrm{of}\mathrm{oil}}{\mathrm{Amount}\mathrm{of}\mathrm{oil}\mathrm{in}1\mathrm{tin}}\\ & =& \frac{313.5}{16.5}\\ & =& 19\mathrm{tins}\end{array}$

Hence, $19\mathrm{tins}$ will be required to hold $313.5\mathrm{litres}$ of oil.