Question

A tin holds $16\frac{1}{2}$ litres of oil.How many such tins will be required to hold $313\frac{1}{2}$ litres of oil?

Answer 1

Capacity of a tin$=16\frac{1}{2}$litres $=\frac{33}{2}$

Tins required to hold $313\frac{1}{2}$ litres of oil$=\frac{313\frac{1}{2}}{16\frac{1}{2}}$

Tins required to hold $313\frac{1}{2}$ litres of oil$=\frac{\frac{627}{2}}{\frac{33}{2}}=\frac{627}{33}=\frac{209}{11}=19$

$\therefore 19$ tins are required to hold $313\frac{1}{2}$ litres of oil.