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Question
A tin holds 33/2 litres, then his many such tins will be required to hold 627/2 litres of oil?
A tin holds 33/2 litres, then his many such tins will be required to hold 627/2 litres of oil?
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Solution
No . Of tins required = (627/2)/(33/2)
= 627/33
= 19
= 627/33
= 19
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