a tin of paint covers a wall area of 8 m2 .A novice wasted 12.5% oh the paint.For painting a circular partition wall of radius 7 m,how many tons would he need?

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Solution

$A r e a p a i n t e d b y a t i n = 8 m^{2} a m o u n t w a s t e d = 12.5 % = \frac{1}{8} a m o u n t u t i l i s e d = 8 - \frac{8}{8} = 8 - 1 = 7 m^{2} A r e a o f w a l l o f r a d i u s 7 m = π 7^{2} = 49 π s i n c e o n e t i n c o v e r s 7 m^{2} t i n r e q u i r e d = \frac{49 π}{7} = 7 π = 7 \times 3.14 = 21.98 a p p r o x i m a t e l y 22 t i n s a r e r e q u i r e d$

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a tin of paint covers a wall area of 8 m2 .A novice wasted 12.5% oh the paint.For painting a circular partition wall of radius 7 m,how many tons would he need?

Area painted by a tin=8m2amount wasted=12.5%=18amount utilised=8-88=8-1=7m2Area of wall of radius 7m=π72=49πsince one tin covers 7m2tin required=49π7=7π=7×3.14=21.98approximately 22 tins are required