Question

A toy rocket is launched with an initial velocity of $12.0m/s$ in the horizontal direction of from the roof of a $37.0m$ tall building. The rocket's engine produces a horizontal acceleration of $2.2m/s^2$ , in the same direction as the initial velocity, but in the vertical direction the acceleration is $9.8m/s^2$ , downward. Air resistance can be neglected. How far does the rocket travel in horizontal direction before it hits the ground? (in m)

• A. $40.4$
  
• B. $40.9$
  
• C. $40.7$
  
• D. $40.3$
  

Answer 1

The correct option is A $40.4$

Time for which rocket will be in air$=\sqrt{\frac{2h}{g}}$$=\sqrt{\frac{2\times 37}{9.8}}=2.7s$

Horizontal distance covered before hitting the ground$=s=ut+\frac{1}{2}a{t}^2=12\times 2.7+0.5\times 2.2\times (2.7{)}^2=40.4m$

Hence correct answer is option $A$