A toy train of mass $1 k g$ moves with a constant velocity of $8 m / s$ , when connected to a battery of $8 V$ for $4 s$ . What is the current in the circuit?

4 A

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2 A

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3 A

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1 A

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Solution

The correct option is D $1 A$
Electrical energy of the battery will be converted into kinetic energy of train.

Kinetic energy of the train = $\frac{1}{2} m v^{2}$ = $\frac{1}{2} \times 1 \times 8^{2}$ = $32 J$

This energy should be equal to the energy produced by battery which is $W = Q V$

$Q V = 32 J$

$Q = \frac{32}{V}$ = $\frac{32}{8}$ = $4 C$

Now current, $I = \frac{Q}{t}$ = $\frac{4}{4}$ = $1 A$

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A toy train of mass 1 kg moves with a constant velocity of 8 m/s, when connected to a battery of 8 V for 4 s. What is the current in the circuit?

A toy train of mass $1 k g$ moves with a constant velocity of $8 m / s$ , when connected to a battery of $8 V$ for $4 s$ . What is the current in the circuit?