A track load of length 4m and magnitude 700 kN is crossing a bridge girder of 20 m span. What would be the maximum BM (in kN-m) at the centre of the girder

3150

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3000

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4500

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5600

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Solution

The correct option is A 3150

Max BM at C = Intensity $\times$ area of shaded ILD

$= 175 (\frac{4 + 5}{2}) \times 2 + 175 (\frac{4 + 5}{2}) 2$

$= 3150 k N m$

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A track load of length 4m and magnitude 700 kN is crossing a bridge girder of 20 m span. What would be the maximum BM (in kN-m) at the centre of the girder

The correct option is A 3150 Max BM at C = Intensity × area of shaded ILD =175(4+52)×2+175(4+52)2 =3150 kN m

The correct option is A 3150

Max BM at C = Intensity $\times$ area of shaded ILD

$= 175 (\frac{4 + 5}{2}) \times 2 + 175 (\frac{4 + 5}{2}) 2$

$= 3150 k N m$