A train $200 m e t r e s$ long is running with a speed of $36 k m / h$ . How much time will it take to pass a standing police?

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Solution

$36 k m \to 1 h r$
$36000 m \to 1 h r$
$200 m \to \frac{200}{36000} h r$

$= \frac{200 \times 60 \times 60}{36000} s e c o n d s$
$= 20 s e c o n d s$

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