1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A train $280m$ long is moving at a speed of $60km/hr$. What is the time taken by it to cross a platform $220m$ long?

Open in App
Solution

## Time taken:Length of the train $=$$280m$Length of the platform $=$ $220m$Hence, to cross the platform completely the train has to cover a distance of$\mathrm{Distance}\mathrm{covered}=\mathrm{length}\mathrm{of}\mathrm{train}+\mathrm{length}\mathrm{of}\mathrm{platform}\phantom{\rule{0ex}{0ex}}\mathrm{Distance}\mathrm{covered}=280+220\mathrm{m}=500\mathrm{m}\phantom{\rule{0ex}{0ex}}\mathrm{Distance}\mathrm{covered}=\frac{500}{1000}\mathrm{km}=0.5\mathrm{km}$Hence, we can find the time as when speed and distance covered is given we use the formula:$\mathrm{Time}\mathrm{taken}=\frac{\mathrm{distance}\mathrm{covered}}{\mathrm{speed}}\phantom{\rule{0ex}{0ex}}\mathrm{Time}\mathrm{taken}=\frac{0.5}{60}\mathrm{hr}=\frac{0.5}{60}×60\mathrm{min}=0.5\mathrm{min}\phantom{\rule{0ex}{0ex}}\mathrm{Time}\mathrm{taken}=0.5×60\mathrm{sec}=30\mathrm{sec}$Therefore, he time taken by it to cross a platform $220m$ long is $30seconds$.

Suggest Corrections
38
Join BYJU'S Learning Program
Related Videos
Distance and Displacement
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program