A train $50 m$ long passes over a bridge at a velocity of $30 k m / h$ . If it takes $36 s$ to cross the bridge, the length of the bridge will be

100 m

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200 m

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250 m

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300 m

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Solution

The correct option is C $250 m$
$30 k m / h = \frac{30}{3.6} m / s = 8.33 m / s$
the distance travelled by train $s p e e d * t i m e = 8.33 * 36 = 300 m$
lenght of bridge+lenght of train=distance travelled by train
$l_{t} + l_{b} = 50 + l_{b} = 300$
$l_{b} = 250 m$

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