A train accelerates from zero to $20 m s^{- 1}$ in $15 s$ . Calculate the distance covered by the train in same time.

194.6 m

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159.6 m

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150 m

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139.6 m

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Solution

The correct option is C $150 m$
Given: initial velocity $u = 0 m s^{- 1}$ , final velocity $v = 20 m s^{- 1}$ , time $t = 15 s$
Using, acceleration $(a) = \frac{v - u}{t} = \frac{20 - 0}{15} = \frac{4}{3} m s^{- 2}$
For distance covered S.
Using, $S = u t + \frac{1}{2} a t^{2} = 0 \times 15 + \frac{1 \times 4 \times 15^{2}}{3 \times 2}$
S = $150 m$

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A train accelerates from zero to 20 ms−1 in 15 s. Calculate the distance covered by the train in same time.

The correct option is C 150 mGiven: initial velocity u=0 ms−1, final velocity v=20 ms−1, time t=15 s Using, acceleration (a)=v−ut=20−015=43 ms−2 For distance covered S. Using, S=ut+12at2=0×15+1×4×1523×2 S = 150 m

A train accelerates from zero to $20 m s^{- 1}$ in $15 s$ . Calculate the distance covered by the train in same time.