Question

A train first travels for $30$ min with a velocity $30km{h}^{-1}$ and then for $40$ min with a velocity $40km{h}^{-1}$ in the same direction, calculate the total distance travelled.

• A. $70km$
• B. $41.67km$
• C. $\frac{490}{6}km$
• D. None of the above

Answer 1

Answer: (B)

$41.67km$

Distance travelled$=velocity\times time$
$\therefore S_1=v_1\times t_1=30\times \frac{1}{2}=15km$
$S_2=v_2\times t_2=40\times \frac{2}{3}=\frac{80}{3}km$
Total distance travelled $S=S_1+S_2$
$=15+\frac{80}{3}=\frac{125}{3}km=41.67km$