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Question

# A train first travels for 30 min with a velocity 30 kmh−1 and then for 40 min with a velocity 40 kmh−1 in the same direction, calculate the average velocity of the train.

A
45.82 kmh1
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B
90.47 kmh1
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C
35.71 kmh1
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D
70.11 kmh1
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Solution

## The correct option is A 35.71 kmh−1Total time of journey t=t1+t2 ⇒t=30+4060=76h∴ Average velocity =Total displacement travelled (S)Total time of journey (t)Total displacement in t1 is s1:s1=3060×30⇒s1=15 kmTotal displacement in t2 is s2:s2=4060×40⇒s2=26.66 kmTotal displacement s in time t:s=41.66 kmVavg=s1+s2tVavg=41.6676Vavg=35.71 kmh−1

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