A train has a speed of $60 k m / h$ for the first one hour and $40 k m / h$ for the next half hour.Its average speed in $k m / h$ is

50

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53.33

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48

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70

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Solution

The correct option is B $53.33$
train has a speed of $60 k m / h$ for the first one hour,
$t_{1} = 1 h r$ , $v_{1} = 60 k m / h r$
Distance covered by the train, $d_{1} = v_{1} t_{1}$
$d_{1} = 60 \times 1 = 60 k m$
For the next half hour, train has speed $40 k m / h r$
$v_{2} = 40 k m / h r$ , $t_{2} = 0.5 h r$
$d_{2} = v_{2} t_{2}$
$d_{2} = 40 \times 0.5 = 20 k m$
Total distance, $d = d_{1} + d_{2}$
$d = 60 + 20 = 80 k m$
Total time, $t = t_{1} + t_{2}$
$t = 1 h r + 0.5 h r = 1.5 h r$
Average speed, $v_{a v g} = \frac{d}{t}$
$v_{a v g} = \frac{80 k m}{1.5 h r} = 53.33 k m / h r$
The correct option is B.

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