Question

A train in motion 66 metres long overtakes a train 88 metres long travelling at 30 km/hour in the opposite direction in 0.168 minute. The speed of the first train is

• A. 20 km/hour
• B. 30 km/hour
• C. 50 km/hour
• D. 25 km/hour

Answer 1

The correct option is D 25 km/hour

Let the speed of the first train is x km/hour
As per question
$\frac{66+88}{(30+x)\times \frac{5}{18}}=0.168\times 60$
$⟹(30+x)=\frac{18\times 154}{5\times 0.168\times 60}=55km/hour$
$\therefore x=55-30=25km/hour$