A train is moving with a velocity of $90 k m p h$ . When brakes are applied, the retardation produced is $0.5 m s^{- 2}$ . Find the time taken by the train to come to rest.

20 s

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30 s

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40 s

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50 s

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Solution

The correct option is D $50 s$
Initial Velocity, $u = 90 k m p h = 25 m s^{- 1}$

Retardation, $a = - 0.5 m s^{- 2}$

Final velocity, $v = 0$

Let time $= t$

$v = u + a t$

$0 = 25 - (0.5 \times t)$

$t = 50 s$

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A train is moving with a velocity of 90 kmph. When brakes are applied, the retardation produced is 0.5ms−2. Find the time taken by the train to come to rest.

The correct option is D 50sInitial Velocity, u=90 kmph=25 ms−1Retardation, a=−0.5 ms−2Final velocity,v=0Let time =tv=u+at0=25−(0.5×t)t=50 s

A train is moving with a velocity of $90 k m p h$ . When brakes are applied, the retardation produced is $0.5 m s^{- 2}$ . Find the time taken by the train to come to rest.

The correct option is D $50 s$
Initial Velocity, $u = 90 k m p h = 25 m s^{- 1}$

Retardation, $a = - 0.5 m s^{- 2}$

Final velocity, $v = 0$

Let time $= t$

$v = u + a t$

$0 = 25 - (0.5 \times t)$

$t = 50 s$