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Question

# A train is running at a speed of 108 km/hr.An inspection cart is also moving with a speed 10m/s in the same direction as train. The train hits the cart (e=12). The velocity of the cart after the collision is nearly

A
20m/s
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B
40m/s
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C
50m/s
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D
cannot determine as the masses of train and cart are not given.
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Solution

## The correct option is C 40m/sA train is running at a speed of.....108km/h=108×518=30m/s.From momentum conservationM×30+m×10=Mv1+mv2....(i)e (velocity of approach) = velocity of separation⇒12×(30−10)=v2−v1⇒10=v2−v1....(ii)On solving,v2=M×40+m×10M+mm/s=40+m.10M1+mM≈40m/s

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