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Question

A train moving at a speed of 30 m/s has just completed a U-curve in a semi-circular track. The engine is at the forward end of the semi-circular part of the track while the last carriage is at the rear end of the semi-circular track. The driver blows a whistle of frequency 200 Hz. If the velocity of sound is 340 m/s, then the apparent frequency as observed by a passenger in the middle of the train is

A
219 Hz
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B
188 Hz
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C
200 Hz
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D
181 Hz
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Solution

The correct option is C 200 Hz

fapp=f0(v±v0v±vs)

V0=302 m/s

Vs=302 m/s

v=340 m/s

fapp=f0(v+v0v+vs)

fapp=200(340+30/2340+30/2)=200 Hz

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