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Standard IX

Physics

The Equations of Motion

A train movin...

Question

A train moving with a velocity of 20 $m s^{- 1}$ is brought to rest by applying brakes in 5 s.Calculate the retardation.

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Solution

Initial velocity u = 20 m/s
Final velocity v = 0
Time taken t = 5 s
Let acceleration be ‘a’.
Using the first equation of motion,
v = u + at
0 = 20 + 5a
a = -4 m/s²
Thus, retardation = 4 m/s²

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The Equations of Motion

Standard IX Physics

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A train moving with a velocity of 20 m s−1 is brought to rest by applying brakes in 5 s.Calculate the retardation.

Initial velocity u = 20 m/s Final velocity v = 0 Time taken t = 5 s Let acceleration be ‘a’. Using the first equation of motion, v = u + at 0 = 20 + 5a a = -4 m/s2 Thus, retardation = 4 m/s2

A train moving with a velocity of 20 $m s^{- 1}$ is brought to rest by applying brakes in 5 s.Calculate the retardation.

Initial velocity u = 20 m/s
Final velocity v = 0
Time taken t = 5 s
Let acceleration be ‘a’.
Using the first equation of motion,
v = u + at
0 = 20 + 5a
a = -4 m/s²
Thus, retardation = 4 m/s²