Question

a train of mass m= pie kg is moving on a circular track of radius R with constant speed v=2 m/s. the length of the train is half of the perimeter of track.The linear momentum will be ?

Answer 1

$$\begin{gathered} linearmomentumwillbemv=2\pi \\ Angularmomentum=mvr \\ lengthofthetrain=halfoftheparameter \\ parameter=2\pi R=2*length \\ r=\frac{2}{R} \\ angularmomentum=\pi \times 2\times \frac{2}{R}=\frac{4\pi }{R} \end{gathered}$$