Question

A train starting from rest moves with a uniform acceleration of 0.2 $m/s^2$ for 5 minutes. Calculate the speed acquired and the distance travelled in this time.

Answer 1

Step 1, Given data

Initial speed = 0
Time taken = 5 min = 300 s
Let final speed be v

Step 2, Finding the final speed

We know,
From equation of motion ,
v = u + at

Putting all the values
= 0 + 0.2 × 300 = 60 m/s

Hence the final speed is 60 m/s

Step 3, Finding the distance traveled

Let the distance traveled be s.

Using the second equation of motion,

$s=ut+\frac{1}{2}a{t}^2$

Putting all the values

$s=0+\frac{1}{2}\times 0.2\times {300}^2$

After solving

s = 9000 m = 9 km

Hence the total distance traveled is 9 km.