Question

A train weighing 1000 tons is moving on a horizontal track with a uniform velocity of $10m/s$.The total resistance to the motion of the train is 5 kgf per ton.If $g=10m/s^2$,then the power of the engine is

Answer 1

Step 1: Given

Mass of train (m)= 1000 ton

Velocity of train (v)= $10m/s$

Step 2: Formula used

Engine power(P) = F*v

1 kgf = 10 N

Step 3: Finding total force

Resistance offered per ton = 5 $\frac{\text{kgf}}{ton}$ = 50 $\frac{\text{N}}{ton}$

The resistance offered for 1000 tonne (F)= 50*1000 = 50000 N

Step 4: Finding power

For moving with constant velocity,

Power, P = 50000*10 W

P = 500* 1000 W

P = 500 KW

Hence, the power of the engine is 500 KW.