A train weighting $10^{7} N$ is running on a level track with uniform speed of $36 k m / h$ . The frictional force is $0.5 k g f$ per quintal. What is the power of the engine?

0.5 k W

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5 k W

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50 k W

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500 k W

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Solution

The correct option is D $500 k W$
Frictional force $= 0.5 k g f = \frac{5}{100} \times 10^{6} = 50000 N$
Uniform speed $= 36 k m p h = 36 \times \frac{5}{18} = 10 m / s$
Power of engine is given by,
$P o w e r = F v$
$= 50000 \times 10$
$= 500000 w a t t$
$= 500 k w$

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A train weighting 107N is running on a level track with uniform speed of 36 km/h. The frictional force is 0.5 kgf per quintal. What is the power of the engine?

The correct option is D 500 kWFrictional force=0.5kgf=5100×106=50000NUniform speed=36kmph=36×518=10m/sPower of engine is given by,Power=Fv =50000×10 =500000watt =500kw

A train weighting $10^{7} N$ is running on a level track with uniform speed of $36 k m / h$ . The frictional force is $0.5 k g f$ per quintal. What is the power of the engine?

The correct option is D $500 k W$
Frictional force $= 0.5 k g f = \frac{5}{100} \times 10^{6} = 50000 N$
Uniform speed $= 36 k m p h = 36 \times \frac{5}{18} = 10 m / s$
Power of engine is given by,
$P o w e r = F v$
$= 50000 \times 10$
$= 500000 w a t t$
$= 500 k w$