A train X starts from a place at a speed of $50$ km/hr. After one hour, another train Y starts from the same place at a speed of $70$ km/hr. After how much time will Y cross X?

3

hrs

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2 \frac{3}{4}

hrs

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3 \frac{1}{2}

hrs

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2 \frac{1}{4}

hrs

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Solution

The correct option is C $3 \frac{1}{2}$ hrs
Suppose they cross after x hours.
Distance covered by Y in $(x - 1)$ hours = Distance covered by X in $x$ hours
$\Rightarrow 70 (x - 1) = 50 x$
$x = 3 \frac{1}{2} h r s .$

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A train X starts from a place at a speed of 50 km/hr. After one hour, another train Y starts from the same place at a speed of 70 km/hr. After how much time will Y cross X?

The correct option is C 312 hrsSuppose they cross after x hours.Distance covered by Y in (x−1) hours = Distance covered by X in x hours⇒70(x−1)=50x x=312hrs.

A train X starts from a place at a speed of $50$ km/hr. After one hour, another train Y starts from the same place at a speed of $70$ km/hr. After how much time will Y cross X?

The correct option is C $3 \frac{1}{2}$ hrs
Suppose they cross after x hours.
Distance covered by Y in $(x - 1)$ hours = Distance covered by X in $x$ hours
$\Rightarrow 70 (x - 1) = 50 x$
$x = 3 \frac{1}{2} h r s .$